Math question! Let θ be an angle in quadrant IV such that cosθ = 3/5. Find the exact values of cscθ and cotθ.?

sin²θ + cos²θ = 1
sin²θ + (3/5)² = 1
sin²θ + (9/25) = 1
sin²θ = 16/25
sinθ = -4/5 or sinθ = 4/5 (rejected, for sinθ < 0 when θ is in quadrant IV.)

cscθ
= 1 / sinθ
= 1 / (-4/5)
= -5/4

cotθ
= cosθ / sinθ
= (3/5) / (-4/5)
= -3/4

cosΘ = 3/5 : Θ in QIV
sinΘ = -4/5
tanΘ = -4/3
cotΘ = -3/4
secΘ = 5/3
cscΘ = -5/4

sin = +/- √(1-cos^2) (negative in q 4)
csc = 1/sin
tan = sin/cos
cot = 1/tan

cos Ө = 3/5______sec Ө = 5/3
sin Ө = 4/5)______csc Ө = 5/4
tan Ө = 4/3______cot Ө = 3/4