Podrian ayudarme a resolver estos radicales pofavooor?, √2 −√3 −√5 / √2 + √3 + √5 de ante mano enserio gracias?

2017-05-28 11:17 am

回答 (2)

2017-05-28 12:05 pm
(√2 - √3 - √5) / (√2 + √3 + √5)

= (√2 - √3 - √5)² / [(√2 + √3 + √5)(√2 - √3 - √5)]

= (2 + 3 + 5 - 2√6 - 2√10 + 2√15) / (2 - 3 - 5 - 2√15)

= (10 - 2√6 - 2√10 + 2√15) / (-6 - 2√15)

= (10 - 2√6 - 2√10 + 2√15)(-6 + 2√15) / [(-6 - 2√15)(-6 + 2√15)]

= (-60 + 12√6 + 12√10 - 12√15 + 20√15 - 12√10 - 20√6 + 60) / (36 - 60)

= (-8√6 + 8√15) / (-24)

= (√6 - √15) / 3
2017-05-28 11:26 am
(sqrt(2) - (sqrt(3) + sqrt(5))) / (sqrt(2) + (sqrt(3) + sqrt(5))) =>
(sqrt(2) - (sqrt(3) + sqrt(5))) * (sqrt(2) - (sqrt(3) + sqrt(5))) / (2 - (sqrt(3) + sqrt(5))^2) =>
(2 - 2 * sqrt(2) * (sqrt(3) + sqrt(5)) + (sqrt(3) + sqrt(5))^2) / (2 - (3 + 2 * sqrt(15) + 5)) =>
(2 - 2 * sqrt(2) * (sqrt(3) + sqrt(5)) + (3 + 2 * sqrt(15) + 5)) / (2 - 8 - 2 * sqrt(15)) =>
(2 + 8 + 2 * sqrt(15) - 2 * (sqrt(6) + sqrt(10)))) / (-6 - 2 * sqrt(15)) =>
-(10 + 2 * sqrt(15) - 2 * (sqrt(6) + sqrt(10)))) / (6 + 2 * sqrt(15)) =>
-(5 + sqrt(15) - sqrt(6) - sqrt(10)) / (3 + sqrt(15)) =>
-(5 + sqrt(15) - sqrt(6) - sqrt(10)) * (3 - sqrt(15)) / (9 - 15) =>
(5 + sqrt(15) - sqrt(6) - sqrt(10)) * (3 - sqrt(15)) / 6 =>
(15 - 5 * sqrt(15) + 3 * sqrt(15) - 15 - 3 * sqrt(6) + sqrt(90) - 3 * sqrt(10) + sqrt(150)) / 6 =>
(15 - 2 * sqrt(15) - 15 - 3 * sqrt(6) + 3 * sqrt(10) - 3 * sqrt(10) + 5 * sqrt(6)) / 6 =>
(15 - 15 - 3 * sqrt(6) + 5 * sqrt(6) + 3 * sqrt(10) - 3 * sqrt(10) - 2 * sqrt(15)) / 6 =>
(2 * sqrt(6) - 2 * sqrt(15)) / 6 =>
(sqrt(6) - sqrt(15)) / 3


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