1.[OH−] = 2.9×10−7 M
2.[OH−] = 1.2×10−11 M
3. [OH−] = 3.4×10−2 M
calculate the ph of each solution?! help!?
2017-05-28 9:04 am
回答 (1)
2017-05-28 10:02 am
1.
pH = 14.0 - pOH = 14.0 + log[OH⁻] = 14.0 + log(2.9 × 10⁻⁷) = 7.5
2.
pH = 14.0 - pOH = 14.0 + log[OH⁻] = 14.0 + log(1.2 × 10⁻¹¹) = 3.1
3.
pH = 14.0 - pOH = 14.0 + log[OH⁻] = 14.0 + log(3.4 × 10⁻²) = 12.5
pH = 14.0 - pOH = 14.0 + log[OH⁻] = 14.0 + log(2.9 × 10⁻⁷) = 7.5
2.
pH = 14.0 - pOH = 14.0 + log[OH⁻] = 14.0 + log(1.2 × 10⁻¹¹) = 3.1
3.
pH = 14.0 - pOH = 14.0 + log[OH⁻] = 14.0 + log(3.4 × 10⁻²) = 12.5
收錄日期: 2021-04-18 16:56:17
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20170528010424AASWNDv