What is the volume of a helium balloon that contains 1.70 mol helium at 27°C and 1.10 atm? show work. a.34.6Lb.34.2L c.38.0Ld.41.9L e.3.77L?

Volume, V = ? L
Pressure, P = 1.10 atm
No. of moles, n = 1.70 mol
Gas constant, R = 0.08206 L atm / (mol K)
Temperature, T = (273 + 27) K = 300 K

For a fixed amount of gas : PV = nRT
Then, V = nRT/P

Volume, V = 1.70 × 0.08206 × 300 / 1.10 L = 38.0 L

The answer : c. 38.0 L