If 89.6 joules of heat are needed to heat 20.0 grams of iron from 30.0°C to 40.0°C, what is the specific heat of the iron in J/g⋅°C?
回答 (2)
2017-05-20 12:00 am
H = m c ΔT
89.6 J = (20.0 g) × c × (40.0 - 30.0)°C
Specific heat of iron, c = 89.6 / [20.0 × (40.0 - 30.0)] J/(g°C) = 0.448 J/(g°C)
89.6 J = (20.0 g) × c × (40.0 - 30.0)°C
Specific heat of iron, c = 89.6 / [20.0 × (40.0 - 30.0)] J/(g°C) = 0.448 J/(g°C)
2017-05-20 12:00 am
The equation:
Heat energy = mass * specific heat * change in temp
89.6 = 20.0*Spec heat *(40.0-30.0)
Specific heat = 89.6/( 20.0*10.0)
Specific heat = 0.448J/g.°C
Heat energy = mass * specific heat * change in temp
89.6 = 20.0*Spec heat *(40.0-30.0)
Specific heat = 89.6/( 20.0*10.0)
Specific heat = 0.448J/g.°C
收錄日期: 2021-04-24 00:29:06
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