how many mL of 0.200 M of aluminum chloride solution will contain 6.00 millimoles of chloride ions?
回答 (2)
2017-05-18 12:45 am
1 mole AlCl₃ contains 3 moles of Cl⁻ ions.
Number of millimoles of Cl⁻ ions = 6.00 mmol
Number of millimoles of AlCl₃ = (6.00 mmol) × (1/3) = 2.00 mmol
Volume of AlCl₃ solution = (2.00 mmol) / (0.200 mmol/mL) = 10.0 mL
Number of millimoles of Cl⁻ ions = 6.00 mmol
Number of millimoles of AlCl₃ = (6.00 mmol) × (1/3) = 2.00 mmol
Volume of AlCl₃ solution = (2.00 mmol) / (0.200 mmol/mL) = 10.0 mL
2017-05-18 1:01 am
Conversions ........ use the unit-factor method and a chain calculation.
0.00600 mol Cl- x (1 mol AlCl3 / 3 mol Cl-) x (1000 mL / 0.200 mol AlCl3) = 10.0 mL
0.00600 mol Cl- x (1 mol AlCl3 / 3 mol Cl-) x (1000 mL / 0.200 mol AlCl3) = 10.0 mL
收錄日期: 2021-04-18 16:11:29
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