If 0.233 moles of zinc reacts with excess lead(IV) sulfate, how many grams of zinc sulfate would be produced in the following reaction?

2Zn + Pb(SO₄)₂ → 2ZnSO₄ + Pb
Mole ratio of Zn : ZnSO₄ = 2 : 2 = 1 : 1
Number of moles of ZnSO₄ produced = (0.233 mol) × 1 = 0.233 mol

Molar mass of ZnSO₄ = (65.4 + 32.1 + 16.0×4) g/mol = 161.5 g/mol
Mass of ZnSO₄ produced = (0.233 mol) × (161.5 g/mol) = 37.6 g

37.6 g