F varies jointly as q1 and q2 and inversely as the square of d. if F =45 when q1 = 15, q2=15, and d=5, find F when q1=8, q2=4, and d=4?

2017-05-09 4:39 am
The variation is F=?
The quantity is F=?

回答 (2)

2017-05-09 5:20 am
✔ 最佳答案
F = k q1 q2 / d²
45 = k 225 / 25
45 = 9 k
k = 5

F = 5 x 32 / 16
F = 10
2017-05-09 4:48 am
F = kq₁q₂/d²
45 = k*15*15/5²
45 = 9k
k = 5

F = 5*8*4/4² = 5*32/16 = 10

A nice inverse square law as in gravity, electric charge, etc.


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