Calculating concentrations with equilibrium constant?

2017-05-09 2:40 am

更新1:

For the reaction H2 (g) + I2 (g) -> 2HI (g) K=50 at 460 C. At equilibrium, the concentration of HI=2.32. Assuming that the concentrations of hydrogen and iodine are identical, what are they? I have a test today, any help would be very appreciated!

回答 (1)

胡雪8°

2017-05-09 3:03 am

_________ H₂(g) + I₂(g) ⇌ 2HI(g) ____ K = 50
At eqm ____ y ____ y ___ 2.32 __ (mol/L)

at equilibrium :
K = [HI]² / ([H₂] [I₂])
50 = 2.32² / y²
y² = 2.32² / 50
y = 2.32 / √50 = 0.328

At equilibrium, [H₂] = [I₂] = 0.328 mol/L

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