Determine which of the gas laws is required to solve each of the following problems. Express answers in correct sig figs and units.?

2017-05-08 8:37 am
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1) A sample of gas occupies 75.0 mL. At 725 mmHg and 18 degrees celsius. Calculate its volume at 800 mmHg and 25.0 degrees celsius.

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2) A container of iodine gas occupies a volume of 3750 mL at 95.15 kPa and 27.5 degrees celsius. At what temperature will the sample occupy 4.00 liters if the pressure remains constant?

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3) A sample of butane gas occupies 8.25 liters at STP. What will be the new volume of the sample if the conditions are changed to 735 mmHg and 20.0 degrees celsius?

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5) Chlorine gas occupies 0.575 liters at 1.50 atm and 125 degrees celsius. At what pressure will the volume be 0.300 liters if the temperature remains constant?

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4) Oxygen gas occupies 2300 mL at 825 torr and 70.0 degrees celsius. What is its new volume at STP?

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6) An 8500 mL tank of gas has a pressure of 200.75 kPa and 20 degrees celsius. What will be the new temperature if its volume is reduced to 6500 mL and the pressure is increased to 250.00 kPa?

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7) A 250 mL flask of gas is at 785 torr of pressure and 25.5 degrees celsius. What will be the pressure of the gas if it is cooled at 0.00 degrees celsius and now occupies 100. mL?

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8) An open 50.0 liter tank of gas if filled to a pressure of 120.0 kPa at 10.0 degrees celsius. What will be its new volume when the pressure increases to 150 kPa but there is no change in temperature?

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9) 5500 mL of hydrogen gas is at STP. What will be the new volume of the sample if the temperature is increases to 75.0 degrees celsius and the pressure remains constant?

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10) The temperature of a container of gas whose pressure is 650 torr is changed from 40.0 degrees celsius to 140.0 degrees celsius. What will be the new pressure?

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11) An equal mixture of oxygen and hydrogen gases is held in a 250.0 liter container at 97.5 kPa and 30.0 degrees celsius. what would be the new volume if the conditions were changed to STP?

回答 (1)

2017-05-08 8:59 am
✔ 最佳答案
1) Boyle's and Charles's Laws:
(75.0 mL) x (725 mmHg / 800 mmHg) x (25.0 + 273) K / (18 + 273) K = 69.6 mL

2) Charles's Law:
(27.5 + 273) K x (4.00 L / 3.750 L) = 321 K


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