323 grams of silicon reacts with 5.49 moles of nitrogen gas to form trisilicon tetranitride
Calculate the theoretical yield of trisilicon tetranitride based upon the initial amount of nitrogen gas.
I got 308.18?
Chem help please?
2017-05-06 12:23 pm
回答 (1)
2017-05-06 12:59 pm
Molar mass of Si = 28.1 g/mol
Initial number of moles of Si = (323 g) / (28.1 g/mol) = 11.5 mol
3Si + 2N₂ → Si₃N₄
Mole ratio N₂ : Si₃N₄ = 2 : 1
When 5.49 moles of N₂ completely reacts :
Maximum number of moles of Si₃N₄ formed = (5.49 mol) × (1/2) = 2.745 mol
Molar mass of Si₃N₄ = (28.1×3 + 14.0×4) g/mol = 140.3 g/mol
Theoretical yield based upon the initial amount of N₂ gas = (2.745 mol) × (140.3 g/mol) = 385 g
Initial number of moles of Si = (323 g) / (28.1 g/mol) = 11.5 mol
3Si + 2N₂ → Si₃N₄
Mole ratio N₂ : Si₃N₄ = 2 : 1
When 5.49 moles of N₂ completely reacts :
Maximum number of moles of Si₃N₄ formed = (5.49 mol) × (1/2) = 2.745 mol
Molar mass of Si₃N₄ = (28.1×3 + 14.0×4) g/mol = 140.3 g/mol
Theoretical yield based upon the initial amount of N₂ gas = (2.745 mol) × (140.3 g/mol) = 385 g
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