If seven times a number is added to the squares of the number and the result is negative twelve, find the numbers.?
回答 (6)
2017-05-05 12:05 am
Let the number be x
7x + x2 = -12
x2 + 7x + 12 = 0
(x + 3) (x + 4) = 0
x = -3 or -4
7x + x2 = -12
x2 + 7x + 12 = 0
(x + 3) (x + 4) = 0
x = -3 or -4
2017-05-05 7:29 am
7 x + x ^ 2 = - 12
x^2 + 7x + 12 = 0
x^2 + 4x + 3 x + 12 = 0
x(x+4) + 3(x+4) = 0
(x+3)(x+4) = 0
x = - 3 and x = - 4
The numbers are - 3 and - 4
x^2 + 7x + 12 = 0
x^2 + 4x + 3 x + 12 = 0
x(x+4) + 3(x+4) = 0
(x+3)(x+4) = 0
x = - 3 and x = - 4
The numbers are - 3 and - 4
2017-05-05 6:36 am
4 and 3
2017-05-05 12:40 am
x² + 7x = -12
x² + 7x + 12 = 0
quadratic formula
x = [-7 ± √(7² – 4·1·12)] / [2·1]
= [-7 ± √1] / 2
= [-7 ± 1] /2
= -4, -3
x² + 7x + 12 = 0
quadratic formula
x = [-7 ± √(7² – 4·1·12)] / [2·1]
= [-7 ± √1] / 2
= [-7 ± 1] /2
= -4, -3
2017-05-05 12:14 am
Let x is a number
Seven timed a number :. 7 x
Add to the square of a number :. + x^2
The result means " is equal to"
Negative 12. :. - 12
The problem is translated :. 7x + x^2 = - 12
Solve:. x^2 + 7 x +. 12. =. 0. =>. ( x + 3)(x+ 4) =. 0
x + 3 = 0. =>. x = - 3
x + 4 =. 0. =>. x = -. 4
Two numbers are - 3 and. -. 4
Seven timed a number :. 7 x
Add to the square of a number :. + x^2
The result means " is equal to"
Negative 12. :. - 12
The problem is translated :. 7x + x^2 = - 12
Solve:. x^2 + 7 x +. 12. =. 0. =>. ( x + 3)(x+ 4) =. 0
x + 3 = 0. =>. x = - 3
x + 4 =. 0. =>. x = -. 4
Two numbers are - 3 and. -. 4
2017-05-05 12:11 am
5
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