calculate the volume of 45.0 grams of carbon dioxide gas at 280 K and 1.2 atm?
回答 (3)
2017-05-03 11:58 pm
Molar mass of CO₂ = (12.0 + 16.0×2) g/mol = 44.0 g/mol
For the sample of CO₂ :
No. of moles, n = 45.0/44.0 mol
Temperature, T = 280 K
Pressure, P = 1.2 atm
Gas constant, R = 0.08206 L atm / (mol K)
For a fixed amount of gas : PV = nRT
Then, V = nRT/P
Volume of CO₂, V = (45.0/44.0) × 0.08206 × 280 / 1.2 = 19.6 L
For the sample of CO₂ :
No. of moles, n = 45.0/44.0 mol
Temperature, T = 280 K
Pressure, P = 1.2 atm
Gas constant, R = 0.08206 L atm / (mol K)
For a fixed amount of gas : PV = nRT
Then, V = nRT/P
Volume of CO₂, V = (45.0/44.0) × 0.08206 × 280 / 1.2 = 19.6 L
2017-05-03 11:46 pm
PV = nRT
P = 1.2 atm
T = 280 K
n = 45.0 g / the molecular weight of CO2 (this puts the answer in moles)
R = 0.08206 L-atm/deg-mol
Solve for V
V = nRT/P
P = 1.2 atm
T = 280 K
n = 45.0 g / the molecular weight of CO2 (this puts the answer in moles)
R = 0.08206 L-atm/deg-mol
Solve for V
V = nRT/P
2017-05-03 11:50 pm
im not sure but my guess is 43.4
收錄日期: 2021-05-01 21:37:25
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