It took 2.74 min with a current of 2.42 A to plate out all the silver from 0.184 L of a solution containing Ag+.?

Amount of electricity passed = (2.42 A) × (2.74 × 60 s) = 398 C

1 mole of electrons carries 96500 C of electricity.
Number of moles of electrons passed = (398 C) / (96500 C/mol) = 0.00412 mol

Ag⁺(aq) + e⁻ → Ag
Mole ratio Ag⁺ : e⁻ = 1 : 1
Number of moles of Ag⁺ in the solution = (0.00412 mol) × 1 = 0.00412 mol

Origin concentration of Ag⁺ in the solution = (0.00412 mol) / (0.184 L) = 0.0224 M