What pressure is required to achieve a CO2 concentration of 9.90×10−2M at 20∘C?
回答 (2)
2017-04-26 11:10 am
✔ 最佳答案
P = nRT / V = (n / V) RT = (9.90 × 10^−2 mol/L) x (0.08205746 L atm/K mol) x (20 + 273) K = 2.38 atm
2017-04-26 10:05 am
For the CO₂ gas :
Concentration, n/V = 9.90 × 10⁻² mol/L
Temperature, T = (273 + 20) K = 293 K
Gas constant, R = 0.08206 L atm / (mol K)
Pressure, P = ? atm
Gas law : PV = nRT
Hence, P = (n/V)RT
Pressure, P = (9.90 × 10⁻²) × 0.08206 × 293 = 2.38 atm
Concentration, n/V = 9.90 × 10⁻² mol/L
Temperature, T = (273 + 20) K = 293 K
Gas constant, R = 0.08206 L atm / (mol K)
Pressure, P = ? atm
Gas law : PV = nRT
Hence, P = (n/V)RT
Pressure, P = (9.90 × 10⁻²) × 0.08206 × 293 = 2.38 atm
收錄日期: 2021-04-20 19:38:41
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https://hk.answers.yahoo.com/question/index?qid=20170426013303AAtZFX5