how many molecules are there in 345 grams of carbon dioxide?
回答 (3)
2017-04-26 8:56 am
Molar mass of CO₂ = (12.0 + 16.0×2) g/mol = 44.0 g/mol
No. of moles of CO₂ = (345 g) / (44.0 g/mol) = 345/44.0 mol
Avogadro constant = 6.02 × 10²³ /mol
Number of CO₂ molecules = (345/44.0 mol) × (6.022 × 10²³ /mol) = 4.72 × 10²⁴
No. of moles of CO₂ = (345 g) / (44.0 g/mol) = 345/44.0 mol
Avogadro constant = 6.02 × 10²³ /mol
Number of CO₂ molecules = (345/44.0 mol) × (6.022 × 10²³ /mol) = 4.72 × 10²⁴
2017-04-26 8:29 am
You're going to be dividing the grams by the molar mass of carbon dioxide, then multiplying it by avogadro's number to get the number of molecules.
So you're going from grams to moles to number of molecules
So you're going from grams to moles to number of molecules
2017-04-26 8:28 am
345 grams of molecules.
收錄日期: 2021-04-18 16:56:14
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