What is the mole fraction of naphthalene in a solution made of 15.00 g of naphthalene (c10h8) and 50.0g of hexane (c6h14)?
回答 (2)
2017-04-26 1:40 am
Molar mass of naphthalene (C₁₀H₈) = (12.0×10 + 1.0×8) g/mol = 128 g/mol
No. of moles of naphthalene in the solution = (15.00 g) / (128 g/mol) = 0.117 mol
Molar mass of hexane (C₆H₁₄) = (12.0×6 + 1.0×14) g/mol = 86.0 g/mol
No. of moles of hexane in the solution = (50.0 g) / (86.0 g/mol) = 0.581 mol
Mole fraction of naphthalene = 0.117 / (0.117 + 0.581) = 0.168
No. of moles of naphthalene in the solution = (15.00 g) / (128 g/mol) = 0.117 mol
Molar mass of hexane (C₆H₁₄) = (12.0×6 + 1.0×14) g/mol = 86.0 g/mol
No. of moles of hexane in the solution = (50.0 g) / (86.0 g/mol) = 0.581 mol
Mole fraction of naphthalene = 0.117 / (0.117 + 0.581) = 0.168
2017-04-26 1:50 am
15.00 g * 1 mole C10H8 /128.17 g = 0.117 moles naphthalene.
50.0 g * 1 / 1 mole C6H14 / 86.18 g = 0.580 moles hexane.
Total moles present = 0.117 + 0.580 = 0.697.
Mole fraction C10H8 = 0.117 / 0.697 = 0.168.
Mole fraction C6H14 = 0.580 / 0.697 = 0.832.
50.0 g * 1 / 1 mole C6H14 / 86.18 g = 0.580 moles hexane.
Total moles present = 0.117 + 0.580 = 0.697.
Mole fraction C10H8 = 0.117 / 0.697 = 0.168.
Mole fraction C6H14 = 0.580 / 0.697 = 0.832.
參考: (0.168 + 0.832 = 1.00).
收錄日期: 2021-04-20 19:38:32
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