f(x)=(2)/(4^(x)+2) f((1)/(2001))+f((2)/(2001))+...+f((2000)/(2001)) 求解?
回答 (1)
2017-04-16 8:54 pm
Sol
f(x)=2/(4^x+2)
f(x)+f(1－x)
=2/[4^x+2]+2/[4^(1－x)+2]
=2/[4^x+2]+2*4^x/[4+2*4^x]
=2/[4^x+2]+4^x/[2+4^x]
=1
A=[f(1/2001)+f(2000/2001)]+[f(2/2001)+f(1999/2001)]+…+[f(1000/2001)+f(1001/2001)]
=1000
f(x)=2/(4^x+2)
f(x)+f(1－x)
=2/[4^x+2]+2/[4^(1－x)+2]
=2/[4^x+2]+2*4^x/[4+2*4^x]
=2/[4^x+2]+4^x/[2+4^x]
=1
A=[f(1/2001)+f(2000/2001)]+[f(2/2001)+f(1999/2001)]+…+[f(1000/2001)+f(1001/2001)]
=1000
收錄日期: 2021-04-30 22:09:44
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20170416103644AAr0nYu