Mg(s) + 2 HCl(aq) MgCl2 (aq) + H2(g) a. What volume of 15.7 M hydrochloric acid will react with 2.1 grams of Mg?
回答 (1)
2017-04-16 12:03 am
Molar mass of Mg = 24.3 g/mol
Mass of Mg reacted = (2.1 g) / (24.3 g/mol) = 0.0864 mol
Mg(s) + 2 HCl(aq) → MgCl₂(aq) + H₂(g)
Mole ratio Mg : HCl = 1 : 2
No. of moles of HCl reacted = (0.0864 mol) × 2 = 0.1728 mol
Volume of HCl needed = (0.1728 mol) / (15.7 mol/L) = 0.0110 L = 11.0 mL
Mass of Mg reacted = (2.1 g) / (24.3 g/mol) = 0.0864 mol
Mg(s) + 2 HCl(aq) → MgCl₂(aq) + H₂(g)
Mole ratio Mg : HCl = 1 : 2
No. of moles of HCl reacted = (0.0864 mol) × 2 = 0.1728 mol
Volume of HCl needed = (0.1728 mol) / (15.7 mol/L) = 0.0110 L = 11.0 mL
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