HELP WITH MATHS NEEDED?

Method I : One linear equation

Let x years old be the age of Thao at present.
Then, Wendy is (x + 30) years old.

Six years ago :
(x + 30) - 6 = 2(x - 6)
24 - x = 2x - 12
x = 36
x + 30 = 66

At present, Wendy is 66 years old and Thao is 36 years old.


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Method II : Simultaneously equations

Let w years old and t years old be the ages of Wendy and Thao respectively.

6 years ago : w - 6 = 2(t - 6) …… [1]
At present : w - t = 30 …… [2]

From [1] :
w - 6 = 2t - 12
w - 2t = -6 …… [3]

[2] - [3] :
t = 36

Substitute t = 36 into [2] :
w - 36 = 30
w = 66

At present, Wendy is 66 years old and Thao is 36 years old.

SIX YEARS AGO
--------------------------

THAO = X

WENDY = 2X

PRESENT AGE
------------------------

THAO = X+6

WENDY = 2X +6

(2X+6) - ( X+6) = 30

X = 30

ANSWER THAO = 36 WENDY = 66 YEARS

Well,

Let w = age of Wendy today
Let t = age of Thao today
then we have
w - 6 = 2(t - 6) ==> w = 2t - 12 + 6 ==> w = 2t - 6
and also
w = t + 30
therefore
2t - 6 = t + 30
t = 36

conclusion :
t = 36
w = 36+30 = 66

qed

hope it' ll help !!

W - 6 = 2 T
W = T + 30

T + 24 = 2T
24 = T (Thao)
54 = W (Wendy)

Let w = current age of Wendy
Let t = current age of Thao.

6 years ago, their ages were (w - 6) and (t - 6)

If wendy was twice the age of thao 6 years ago, then:

w - 6 = 2(t - 6)

Let's add 6 to this and simplify (you'll see why shortly)

w = 6 + 2(t - 6)
w = 6 + 2t - 12
w = 2t - 6

Then you are told that Wendy's current age is 30 years older than Thao, so:

w = t + 30

Now we have two equations and two unknowns, both equal to w in terms of t, so we can set both of the right-sides equal to each other and solve for t:

2t - 6 = t + 30
t = 36

Now that we have t, solve for w:

w = t + 30
w = 36 + 30
w = 66

So Wendy is now 66 years old and Thao is 36 years old.

6 years ago, they were 60 and 30, twice the age of the other.