which of the following equations describes a line perpendicular to the line y=7x+49?

2017-04-08 12:47 am
更新1:

If two lines are perpendicular, then the slope of one is the negative reciprocal of the slope of the other.

更新2:

A) y=-7x-49 B) y=-1/7x+10 C) y=1/7x+7 D) y=7x-49 E) y=7x+14

回答 (5)

2017-04-08 12:55 am
✔ 最佳答案
B) y=-1/7x+10
2017-04-08 12:56 am
The slope of the line y = 7x + 49 is equal to 7.
Then, slope of the line which is perpendicular to y = 7x + 9 should be -1/7.

A) Slope of the line y = -7x - 49 is equal to -7.
B) Slope the line y = (-1/7)x + 10 is equal to -1/7
C) Slope of the line y = (1/7)x + 7 is equal to 1/7.
D) Slope of the line y = 7x - 49 is equal to 7.
E) Slope of the line y = 7x + 14 is equal to 7.

The answer: y = (-1/7)x + 10
2017-04-08 1:34 am
y = (-1/7) x + 10
2017-04-08 1:08 am
m1*m2 = -1, where m1 & m2 are the slopes of two prependicular lines.
Therefore, Answer is B
2017-04-08 12:57 am
B because it is the only answer choice with a negative reciprocal of the slope of the original line ( have to think logically too when solving a problem)


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