which of the following equations describes a line perpendicular to the line y=7x+49?

B) y=-1/7x+10

The slope of the line y = 7x + 49 is equal to 7.
Then, slope of the line which is perpendicular to y = 7x + 9 should be -1/7.

A) Slope of the line y = -7x - 49 is equal to -7.
B) Slope the line y = (-1/7)x + 10 is equal to -1/7
C) Slope of the line y = (1/7)x + 7 is equal to 1/7.
D) Slope of the line y = 7x - 49 is equal to 7.
E) Slope of the line y = 7x + 14 is equal to 7.

The answer: y = (-1/7)x + 10

y = (-1/7) x + 10

m1*m2 = -1, where m1 & m2 are the slopes of two prependicular lines.
Therefore, Answer is B

B because it is the only answer choice with a negative reciprocal of the slope of the original line ( have to think logically too when solving a problem)