∫2^x sin2^x dx這題怎麼解?
回答 (1)
2017-04-07 2:09 pm
Sol
Set y=2^x
dy/dx=d2^x/dx=2^xln2
dy=2^xln2dx
∫2^xSin2^x dx
=(1/ln2)∫2^xln2Sin2^x dx
=(1/ln2)∫Sinydy
=－(1/ln2)Cosy+c
=－Cos2^x/ln2+c
螞蟻雄兵 · 1 分前
Set y=2^x
dy/dx=d2^x/dx=2^xln2
dy=2^xln2dx
∫2^xSin2^x dx
=(1/ln2)∫2^xln2Sin2^x dx
=(1/ln2)∫Sinydy
=－(1/ln2)Cosy+c
=－Cos2^x/ln2+c
螞蟻雄兵 · 1 分前
收錄日期: 2021-04-30 22:10:16
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