Standard Normal Distribution Problem. We were given the answer and we're supposed to give the solution.The answer is 53.04. But how?
2017-04-06 9:14 am
R.A. Fisher proved that when n is greater than or equal to 30 and Y has chi square distribution with n degrees freedom, then sqrt(2Y) - sqrt(2n-1) has an Approximate Standard Normal Distribution. Under this approximation, what s the 90th percentile of Y when n=41
回答 (1)
2017-04-06 3:19 pm
✔ 最佳答案
Z= √(2Y) - √(2n-1)
= √(2Y) - √(2*41-1)
= √(2Y) - √81
= √(2Y) - 9
Since P( Z ≦ 1.282 ) ≒ 0.9 , we have
√(2Y) - 9 = 1.282
√(2Y) = 10.282
2Y = 10.282² ≒ 105.7195
Y = 105.7195 / 2 ≒ 52.86
收錄日期: 2021-05-02 14:10:47
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