The reaction 2NO2 2NO + O2 is second order with respect to NO2. If initial concentration of
NO2 (g) is 6.54 ×10-4 mol L-1
, what is the rate constant if initial reaction rate is 4.42 ×10-7 mol L-1s-1? What is the half-life of system?
ChEMISTRY?
2017-04-05 2:41 pm
回答 (1)
2017-04-05 4:00 pm
2NO₂(g) → 2NO(g) + O₂(g)
Rate = k [NO₂]²
When [NO₂]ₒ = 6.54 × 10⁻⁴ mol L⁻¹, Rate = 4.42 × 10⁻⁷ mol L⁻¹ s⁻¹ :
4.42 × 10⁻⁷ mol L⁻¹ s⁻¹ = k (6.54 × 10⁻⁴ mol L⁻¹)²
k = 1.03 L mol⁻¹ s⁻¹
For a second order reaction, Half-life = 1 / (k [NO₂]ₒ)
which depends on the initial concentration.
When [NO₂]ₒ = 6.54 × 10⁻⁴ mol L⁻¹ :
Half-life of the system = 1 / [(1.03 L mol⁻¹ s⁻¹) × (6.54 × 10⁻⁴ mol L⁻¹) = 1480 s
Rate = k [NO₂]²
When [NO₂]ₒ = 6.54 × 10⁻⁴ mol L⁻¹, Rate = 4.42 × 10⁻⁷ mol L⁻¹ s⁻¹ :
4.42 × 10⁻⁷ mol L⁻¹ s⁻¹ = k (6.54 × 10⁻⁴ mol L⁻¹)²
k = 1.03 L mol⁻¹ s⁻¹
For a second order reaction, Half-life = 1 / (k [NO₂]ₒ)
which depends on the initial concentration.
When [NO₂]ₒ = 6.54 × 10⁻⁴ mol L⁻¹ :
Half-life of the system = 1 / [(1.03 L mol⁻¹ s⁻¹) × (6.54 × 10⁻⁴ mol L⁻¹) = 1480 s
收錄日期: 2021-04-18 16:08:35
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https://hk.answers.yahoo.com/question/index?qid=20170405064145AAToI84