A smooth spherical object is projected horizontally from a point a vertical height H = 26.18 metres above horizontal ground with?

The vertical motion is in uniform acceleration :
u(y) = 0 m s⁻¹
a(y) = 9.81 m s⁻²
s(y) = 26.18 m

Formula used : s(y) = u(y) t + (1/2) a(y) t²
26.18 = 0 + (1/2) * 9.81 * t²
t² = 52.36/9.81 s²
t = 2.31 s

The horizontal motion is in uniform speed :
v(x) = 21.83 m s⁻¹
t = 2.31 s

Formula used : s(x) = v(x) t
s(x) = 21.83 × 2.31 m = 50.4 m