Math 圓的性質 急！！?
回答 (1)
2017-04-02 8:54 am
Set angle a = ∠BCE = ∠BCD = arc(BD)/2
for ΔACE: 2a + 15° + 63° + 90° = 180° ==>> a = 6°
for ΔBCE: x + 6° + 63° + 90° = 180° ==>> x = 21° = (B)
Answer = (B)
for ΔACE: 2a + 15° + 63° + 90° = 180° ==>> a = 6°
for ΔBCE: x + 6° + 63° + 90° = 180° ==>> x = 21° = (B)
Answer = (B)
收錄日期: 2021-05-01 15:26:51
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