Math 圓的性質 急!!?

2017-04-01 6:17 pm
求詳解

回答 (1)

2017-04-02 8:54 am
Set angle a = ∠BCE = ∠BCD = arc(BD)/2

for ΔACE: 2a + 15° + 63° + 90° = 180° ==>> a = 6°

for ΔBCE: x + 6° + 63° + 90° = 180° ==>> x = 21° = (B)

Answer = (B)


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