Logarithms?
回答 (3)
2017-04-01 2:41 am
Whatever you understand underneath an 'exponential equation', the answer is most likely yes as there are many equations that have no solutions, no real solutions.
e.g.
exp(x) + 1 = 0
has no real solutions as exp(x) > 0.
e.g.
exp(x) + 1 = 0
has no real solutions as exp(x) > 0.
2017-04-01 3:00 am
Sure. e^x = 0 has no solutions.
2017-04-01 2:48 am
y = e^x is positive for all values of x.
y = - 17 is negative for all values of x.
These two equations do not intersect, so there is no solution.
y = - 17 is negative for all values of x.
These two equations do not intersect, so there is no solution.
收錄日期: 2021-04-24 00:19:14
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