數學 圓的性質 急！！?
回答 (1)
2017-04-01 12:07 am
✔ 最佳答案
∠DBC + ∠CDB = ∠ACB (∠BCE + ∠BEC) + ∠CDB = ∠ACB
(∠BCE + ∠BAC) + ∠CDB = ∠ACB
(∠BCE + 33°) + 48° = 90°
∠BCE = 90° - 48° - 33° = 9° , 答: B.
收錄日期: 2021-04-11 21:36:35
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20170331142714AAkDfQZ