16^(x+2) = 8^-x? Solve for x?
回答 (2)
2017-03-25 7:24 am
16^(x + 2) = 8^-x
2^(4x + 8) = 2^(-3x)
4x + 8 = -3x
x = -8/7
2^(4x + 8) = 2^(-3x)
4x + 8 = -3x
x = -8/7
2017-03-25 6:18 am
already posted and answered
2^(4(x+2))=2^(-3x)
4x+8=-3x
7x=-8
x=-8/7
2^(4(x+2))=2^(-3x)
4x+8=-3x
7x=-8
x=-8/7
收錄日期: 2021-04-24 00:24:31
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