1+2+3+4+5+6+...+100?

👨🏻‍🏫 學術台數學

Ryan-ivan

2017-03-23 6:12 pm

回答 (9)

一哥

2017-04-20 1:00 pm

1+2+3+4+5+6+...+100
=(最大数+最小数)x中间数
=1+100)x50
=5050

👍 1 👎 0

家駒

2017-03-24 11:48 pm

n
∑ k =n(n+1)/2
k=1

n=100代入

100×101÷2
=5050

A:5050

👍 1 👎 0

pui

2017-03-24 4:09 pm

1+2+3+4+5+6+...+100
=(1+100)*100/2
=5050

👍 1 👎 0

Kan

2017-05-04 8:22 pm

1+2+3+4+5+6+7+8+9+10x10=5500/5050

👍 1 👎 1

[匿名]

2017-05-09 8:36 pm

5050

👍 0 👎 0

mandy

2017-05-05 10:20 pm

5050 is definitely the answer!

👍 0 👎 0

[匿名]

2017-04-25 11:20 pm

5050

(1+100)/100/2

👍 0 👎 0

[匿名]

2017-04-14 12:25 pm

5050

👍 0 👎 0

[匿名]

2017-03-26 11:57 am

1+2+3+4+5+6...+100
=(1+100)x50
=5050

👍 0 👎 0