1+2+3+4+5+6+...+100?

2017-03-23 6:12 pm

回答 (9)

2017-04-20 1:00 pm
1+2+3+4+5+6+...+100
=(最大数+最小数)x中间数
=1+100)x50
=5050
2017-03-24 11:48 pm
n
∑ k =n(n+1)/2
k=1

n=100代入

100×101÷2
=5050

A:5050
2017-03-24 4:09 pm
1+2+3+4+5+6+...+100
=(1+100)*100/2
=5050
2017-05-04 8:22 pm
1+2+3+4+5+6+7+8+9+10x10=5500/5050
2017-05-09 8:36 pm
5050
2017-05-05 10:20 pm
5050 is definitely the answer!
2017-04-25 11:20 pm
5050

(1+100)/100/2
2017-04-14 12:25 pm
5050
2017-03-26 11:57 am
1+2+3+4+5+6...+100
=(1+100)x50
=5050


收錄日期: 2021-04-18 16:12:08
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