MATH!!! HELP NOW PLEASE! :( ASAP?
回答 (1)
2017-03-20 9:02 am
You are given
f(x) = a (x-h)^2 +k. Use he conditions
y=0, x=0
a h^2 +k=0.
Find the minima
df/dx= 0 = 2a(x-h) . This gives x=h at x=2, h=2.
Therefore, you have
4a+k=0
Use the other condition
When x=2, y=-24
-24 =k,
k=-24, -k=4a, This gives a=4. The solution wll be
f(x) = 4(x-2)^2 -24
This is the answer.
f(x) = a (x-h)^2 +k. Use he conditions
y=0, x=0
a h^2 +k=0.
Find the minima
df/dx= 0 = 2a(x-h) . This gives x=h at x=2, h=2.
Therefore, you have
4a+k=0
Use the other condition
When x=2, y=-24
-24 =k,
k=-24, -k=4a, This gives a=4. The solution wll be
f(x) = 4(x-2)^2 -24
This is the answer.
收錄日期: 2021-04-24 00:22:15
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