(x) - (x^2)/(x - 2) + (9)/(x^2 - 4) May someone help me combine these 3 fractions, because it says my answer is wrong.?

x - [x²/ (x - 2)] + [9 / (x² - 4)]
= [x(x + 2)(x - 2) / (x + 2)(x - 2)] - [x²(x + 2) / (x + 2)(x - 2)] + [9 / (x + 2)(x - 2)]
= [x(x² - 4) / (x + 2)(x - 2)] - [(x³ + 2x²) / (x + 2)(x - 2)] + [9 / (x + 2)(x - 2)]
= [(x³ - 4x) / (x + 2)(x - 2)] - [(x³ + 2x²) / (x + 2)(x - 2)] + [9 / (x + 2)(x - 2)]
= [(x³ - 4x) - (x³ + 2x²) + 9] / (x + 2)(x - 2)
= [x³ - 4x - x³ - 2x² + 9] / (x + 2)(x - 2)
= [-2x² - 4x + 9] / (x + 2)(x - 2)
= -(2x² + 4x - 9) / (x + 2)(x - 2)

The answer can also be written as: -(2x² + 4x - 9) / (x² - 4)

x (x - 2) (x + 2) - (x²) (x + 2) + 9
-----------------------------------------------
(x - 2) (x +2)

x (x² - 4) - x³ - 2x² + 9
---------------------------------
(x - 2) (x +2)

9 - 4x - 2x²
-------------------
(x - 2) (x +2)

(x) - (x^2)/(x - 2) + (9)/(x^2 - 4)

= [x(x - 2) - x^2]/(x - 2) + 9/(x^2 - 4)

= [ x^2 - 2x - x^2]/(x - 2) + 9/(x^2 - 4)

= - 2x/(x + 2) + 9/(x^2 - 4)

= (- 2x^2 - 4x + 9)/(x^2 - 4)

= ( 9 - 4x - 2x^2)/(x^2 - 4)

First give the three terms a common denominator.
The least common denominator is x²-4.

(x) = (x²)/(x - 2) + 9/x² - 4

X(x² - 4) - x²(x + 2) + 9/(x² - 4)

X³ - 4x - x³ - 2x² + 9/(x² - 4)

- 2x² - 4x + 9/(x2 - 4)

[(x) - (x^2)] / [(x - 2) + (9)] / [(x^2 - 4)]
= [x(1 - x) / (x - 2) + (9) / [(x^2 - 4)]
= [x(1 - x)(x + 2) + 9] / [(x^2 - 4)]
Quotient and remainder:
-x^3 - x^2 + 2 x + 9 = (-x - 1) × (x^2 - 4) + 5 - 2 x