求交點 有兩條線分別各2個座標 左邊x右邊y 第一組座標 {0.0962, -0.4934} { 0.1022, -0.4931} 第二組 {0.1123, -0.4976} { 0.1118, -0.5037} 一直算不出來 希望有詳解?

m L1
=(-0.4934+0.4931)/(0.0962-0.1022)
=1/20
y=x/20 +c
-0.4934=0.0962/20+c
c=-0.49821
y=x/20-0.49821
x-20y=9.9642 i

m L2
=(-0.4976+0.5037)/(0.1123-0.1118)
=61.5
y=61x/5 +c
-0.5037=61(0.1118)/5 +c
c=-1.86766
y=61x/5 -1.86766
61x-y=9.3383 ii

x=0.145038392
y=-0.49095808

第一組座標 {0.0962, -0.4934} { 0.1022, -0.4931}
第二組 {0.1123, -0.4976} { 0.1118, -0.5037}

第一條直線 (y+0.4934)=(x-0.0962)*(-0.4931+0.4934)/(0.1022-0.0962)
(y+0.4934)=(x-0.0962)*(0.0003)/(0.006)
(y+0.4934)=(x-0.0962)/20 ...(1)
第二條直線 (y+0.4976)=(x-0.1123)*(-0.4976+0.5037)/(0.1123-0.1118)
(y+0.4976)=(x-0.1123)*(0.0061)/(0.0005)
(y+0.4976)=(x-0.1123)*(61/5) .....(2)
(2)-(1)
0.0042= (61/5-1/20) x - 0.1123*61/5 + 0.0962/20
(243/20) x = 0.0042+1.37006-0.00481
12.15 x = 1.36945
x ~ 0.11271193
y~ - 0.4925744