prepare 0.350 L of 0.900 M HCl solution, starting with a 2.00 M HCl solution. What volume (in L) of the 2.00 M solution will you need?
回答 (1)
2017-03-10 11:56 pm
Stock solution: M₁ = 2.00 M, V₁ = ? L
Diluted solution: M₂ = 0.900 M, V₂ = 0.350 L
M₁V₁ = M₂V₂
Then, V₁ = V₂ × (M₂/M₁)
Volume of 2.00 M solution needed, V₁ = (0.350 L) × (0.900/2.00) = 0.158 L
(to 3 sig. fig.)
Diluted solution: M₂ = 0.900 M, V₂ = 0.350 L
M₁V₁ = M₂V₂
Then, V₁ = V₂ × (M₂/M₁)
Volume of 2.00 M solution needed, V₁ = (0.350 L) × (0.900/2.00) = 0.158 L
(to 3 sig. fig.)
收錄日期: 2021-04-18 16:04:48
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