Chemistry help?

A mass of glycine (0.8374 g) is to be neutralized with a solution of NaOH (0.09454 M). Calculate the volume of the NaOH solution required.

Molar mass of H₂NCH₂COOH (glycine) = (1.0×5 + 14.0 + 12.0×2 + 16.0×2) g/mole = 75.0 g/mole
No. of moles of H₂NCH₂COOH reacted = (0.8374 g) / (75.0 g/mole) = 0.011165 mole

The equation for the neutralization of glycine against NaOH is :
H₂NCH₂COOH(aq) + NaOH(aq) →H₂NCH₂COONa(aq) + H₂O(l)
Mole ratio H₂NCH₂COOH : NaOH = 1 : 1
No. of moles of NaOH required = 0.011165 mole

Molarity of NaOH = 0.09454 M = 0.09454 mole/L
Volume of NaOH required = (0.011165 mole) / (0.09454 mole/L) = 0.1181 L = 118.1 mL


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Write balanced equations showing the coordination of Ni²⁺ ions with six chloride ions and 3 oxalate (C₂O₄²⁻) ions in solution.

Ni²⁺(aq) + 3 C₂O₄²⁻(aq) → [Ni(C₂O₄)₃]⁴⁻(aq)