Given the points (3,6) and (0,1) What is the slope, and equation of the line between these two points?

m = - 5 / - 3
m = 5 / 3

y - 6 = (5/3) (x - 2 )
y = (5/3) x - 10/3 + 18/3
y = (5/3) x + 8/3

The slope of the line between the two points
= (6 - 1)/(3 - 0)
= 5/3

The equation of the line between the two points :
(y - 1)/(x - 0) = 5/3
(y - 1)/x = 5/3
5x = 3(y - 1)
5x = 3y - 3
5x - 3y + 3 = 0

m = slope = (1 - 6) / (0 - 3) = +5/3
y = mx + b;
where if (x, y) then (0, b), so:
y = +5/3 x + 1

Equation of a straight line : y=ax+b
a: the slope
b: y-intercept

Slope = rise/run
= yA-yB / xA-xB
= 6-1 / 3-0
a = 5/3

Since y=ax+b
So,y=5x/3 + b
But since the line passes through point(0,1) , it must satisfy the equation

So, 1=5(0)x/3 +b (substitute the coordinates of the point in the equation of the line to find b)

b=1

So the equation of the line is y=5x/3 +1