Calculate the mass of 6.02*10^21 molecules of nitrogen.?
回答 (1)
2017-03-08 4:03 pm
1 mole of N₂ (nitrogen) contains 6.02 × 10²³ molecules of N₂.
No. of moles of N₂ = (6.02 × 10²¹) / (6.02 × 10²³) = 0.0100 mol
Molar mass of N₂ = 14.0 × 2 g/mol = 28.0 g/mol
Mass of N₂ = (0.0100 mol) × (28 g/mol) = 0.280 g
No. of moles of N₂ = (6.02 × 10²¹) / (6.02 × 10²³) = 0.0100 mol
Molar mass of N₂ = 14.0 × 2 g/mol = 28.0 g/mol
Mass of N₂ = (0.0100 mol) × (28 g/mol) = 0.280 g
收錄日期: 2021-04-18 16:03:18
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