1) x+1 = 2(x+1)
2) 9(x+7)= 2(5x-7)
3) 3(x+4)= 5(x-2)
solve equations?
2017-03-08 2:25 am
回答 (5)
2017-03-08 2:37 am
1)
x + 1 = 2x + 2
x + 1 = 2x + 2
- 1 = x
2)
9x + 63 = 10x - 14
77 = x
3)
3x + 12 = 5x - 10
22 = 2x
x = 11
x + 1 = 2x + 2
x + 1 = 2x + 2
- 1 = x
2)
9x + 63 = 10x - 14
77 = x
3)
3x + 12 = 5x - 10
22 = 2x
x = 11
2017-03-08 2:32 am
1) x+1 = 2(x+1)
2x + 2 = x + 1
2x - x = 1 - 2
x = - 1
2) 9(x+7)= 2(5x-7)
9x + 63 = 10x - 14
10x - 9x = 63 + 14
x = 77
3) 3(x+4)= 5(x-2)
5(x - 2) = 3(x + 4)
5x - 10 = 3x + 12
5x - 3x = 12 + 10
2x = 22
x = 11
2x + 2 = x + 1
2x - x = 1 - 2
x = - 1
2) 9(x+7)= 2(5x-7)
9x + 63 = 10x - 14
10x - 9x = 63 + 14
x = 77
3) 3(x+4)= 5(x-2)
5(x - 2) = 3(x + 4)
5x - 10 = 3x + 12
5x - 3x = 12 + 10
2x = 22
x = 11
2017-03-08 2:52 pm
1) x + 1 = 2(x + 1)
x + 1 = 2x + 2
- x = 1
or
x = - 1.
the rest of these are your homework, not mine.
x + 1 = 2x + 2
- x = 1
or
x = - 1.
the rest of these are your homework, not mine.
2017-03-08 2:38 am
(x+1) = 2(x+1)
(x+1) - (x+1) = 2(x+1) - (x+1)
0 = x+1
x = -1
(x+1) - (x+1) = 2(x+1) - (x+1)
0 = x+1
x = -1
2017-03-08 2:28 am
Here's #3:
Expand terms on both sides, giving 3x + 12 = 5x - 10.
Subtract 3x from both sides, giving
12 = 2x - 10.
Add 10 to both sides, giving
22 = 2x.
Divide both sides by 2, giving
x = 11.
The others are done in the same way. Good luck, and good studying!
Expand terms on both sides, giving 3x + 12 = 5x - 10.
Subtract 3x from both sides, giving
12 = 2x - 10.
Add 10 to both sides, giving
22 = 2x.
Divide both sides by 2, giving
x = 11.
The others are done in the same way. Good luck, and good studying!
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