What volume of CO2(g) is formed when 23.9 L of C7H16 (g) is burned? Assume that both gases are measured under the same conditions.
Express the volume to three significant figures and include the appropriate units.
Consider the following equation, which represents the combustion (burning) of heptane (C7H16). C7H16(g)+11O2(g)→7CO2(g)+8H2O(g)?
2017-02-26 3:23 pm
回答 (2)
2017-02-26 8:49 pm
C₇H¬₁₆(g)+11O₂(g)→7CO₂(g)+8H₂O(g)
Volume ratio C₇H¬₁₆ : CO₂ = 1 : 7
Volume of C₇H¬₁₆ burned = 23.9 L
Volume of CO₂ formed = (23.9 L) × 7 = 167.3 L
Volume ratio C₇H¬₁₆ : CO₂ = 1 : 7
Volume of C₇H¬₁₆ burned = 23.9 L
Volume of CO₂ formed = (23.9 L) × 7 = 167.3 L
2017-02-26 3:41 pm
Never mind I've figured it out.
All you need to do is: multiply 23.9L with amount of CO2 on the other side of C7H16 (which is 7) and you get 167.3L
All you need to do is: multiply 23.9L with amount of CO2 on the other side of C7H16 (which is 7) and you get 167.3L
收錄日期: 2021-04-20 19:33:25
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