steps for 4(3x-3)^2/3=36 find x?
回答 (1)
2017-02-24 4:10 pm
4 (3x - 3)^(2/3) = 36
(3x - 3)^(2/3) = 9
[(3x - 3)^(2/3)]^3 = 9^3
(3x - 3)^2 = 729
9x² - 18x + 9 = 729
x² - 2x + 1 = 81
x² - 2x - 80
(x - 10)(x + 8) = 0
x = 10 or x = -8
(3x - 3)^(2/3) = 9
[(3x - 3)^(2/3)]^3 = 9^3
(3x - 3)^2 = 729
9x² - 18x + 9 = 729
x² - 2x + 1 = 81
x² - 2x - 80
(x - 10)(x + 8) = 0
x = 10 or x = -8
收錄日期: 2021-05-01 13:08:36
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20170224075308AAahoV4