how does change in velocity divided by change in time equal m/s^2? (m/s final - m/s initial / s finals and s initial ) = m/s^2?
回答 (4)
2017-02-24 3:27 pm
The unit of velocity is m/s while the unit of time is s.
Hence, the unit of change in velocity (i.e. final velocity - initial velocity) is m/s,
and the unit of change in time (i.e. final time - initial time) is s.
The unit of (change in time ÷ change in time)
= (m/s) ÷ s
= (m/s) × (1/s)
= m/s²
Hence, the unit of change in velocity (i.e. final velocity - initial velocity) is m/s,
and the unit of change in time (i.e. final time - initial time) is s.
The unit of (change in time ÷ change in time)
= (m/s) ÷ s
= (m/s) × (1/s)
= m/s²
2017-02-24 3:18 pm
a = (vf - vi)/(tf - ti)
Unit of (vf - vi) = m/s
Unit of (tf - ti) = s
So, a = (m/s)/s = m/s^2
Unit of (vf - vi) = m/s
Unit of (tf - ti) = s
So, a = (m/s)/s = m/s^2
2017-02-25 12:05 pm
You can say = 1/s (m/s final - m/s initial) when s tends to zero. Like taking the limit.
2017-02-24 3:05 pm
K
收錄日期: 2021-04-18 16:05:04
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