Please help me solve this trigonometry problem!?
回答 (3)
2017-02-24 2:40 pm
y = 300 tan x
When y = -820 :
-820 = 300 tan x
tan x = -820/300
x = arctan(-820/300)
x = 180° - 70° …… for arctan(820/300) = 70°
x = 110°
The ordered pair = (110°, -820)
When y = -820 :
-820 = 300 tan x
tan x = -820/300
x = arctan(-820/300)
x = 180° - 70° …… for arctan(820/300) = 70°
x = 110°
The ordered pair = (110°, -820)
2017-02-24 2:42 pm
You are given a function, and are asked to find a specified point.
y = 300*tan(x)
Point is (x°,-820)
Substitue: -820 = 300*tan(x)
tan(x) = -2.73333....
x = arctan(-2.73333...) ≈ -69.9°
y = 300*tan(x)
Point is (x°,-820)
Substitue: -820 = 300*tan(x)
tan(x) = -2.73333....
x = arctan(-2.73333...) ≈ -69.9°
2017-02-24 2:40 pm
y = -820
300tan(x) = -820
tan(x) = -41/15
x = tan⁻¹(-41/15) + 180°
x ≈ 110.1°
300tan(x) = -820
tan(x) = -41/15
x = tan⁻¹(-41/15) + 180°
x ≈ 110.1°
收錄日期: 2021-04-18 16:06:30
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