✔ 最佳答案
The diagonal of the face a unit cell of FCC
= 4 × (atomic radius)
= 4 × (321 pm)
= 1284 pm
The length of edge of a unit cell
= 1284/√2 pm
= (1284/√2) × 10⁻¹⁰ cm
The volume of a unit cell
= [(1284/√2) × 10⁻¹⁰]³ cm³
Mass of a unit cell
= {[(1284/√2) × 10⁻¹⁰]³ cm³} × (19.3 g/cm³)
= (1284/√2)³ × 10⁻³⁰ × 19.3 g
Number of atoms in a unit cell
= 8 × (1/8 atom at corner) + 6 × (1/2 atom on face)
= 4 atoms
No. of moles of atoms in a unit cell
= [4/(6.022 × 10²³)] mol
Molar mass for the element
= [(1284/√2)³ × 10⁻³⁰ × 19.3 g] / {[4/(6.022 × 10²³)] mol}
= 2174 g/mol