How many moles are in a mass of 5.6g of NaBrO3?
回答 (3)
2017-02-20 4:17 pm
Molar mass of NaBrO₃ = (23.0 + 79.9 + 16.0×3) g/mol = 150.9 g/mol
No. of moles of NaBrO₃ = (5.6 g) / (150.9 g/mol) = 0.037 mol (to 2 sig. fig.)
No. of moles of NaBrO₃ = (5.6 g) / (150.9 g/mol) = 0.037 mol (to 2 sig. fig.)
2017-02-20 2:58 pm
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NaBrO
NaBrO
2017-02-20 3:21 pm
0.037 mole.
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