I've been stuck on these questions and don't know what to do! If you could also provide the work so I can know how you solved it that would be great. Thanks!
1. Use the given values to evaluate (if possible) the remaining trigonometric functions.
Given: sin Ø = 2/√5 and cos Ø = 1/√5
2. Solve the equation on the interval [0,2pi)
sin Ø cos Ø = -1/2
Trig questions please help?
2017-02-17 9:38 am
回答 (1)
2017-02-17 9:50 am
✔ 最佳答案
1.sinϕ = 2/√5
cosϕ = 1/√5
tanϕ = sinϕ / cosϕ
= (2/√5) / (1/√5)
= 2
secϕ = 1 / cosϕ
= 1 / (1/√5)
= √5
cscϕ = 1 / sinϕ
= 1 / (2/√5)
= (√5)/2
cotϕ = 1 / tanϕ
= 1/2
====
2.
0 ≤ ϕ < 2π
Then, 0 ≤ 2ϕ < 4π
sinϕ cosϕ = -1/2
(1/2) (2 sinϕ cosϕ) = -1/2
(1/2) sin(2ϕ) = -1/2
sin(2ϕ) = -1
2ϕ = 3π/2 or 2ϕ = 2π + (3π/2)
ϕ = 3π/4 or ϕ = 7π/4
收錄日期: 2021-05-01 13:43:24
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20170217013855AAdDX4z