Can someone explain to me step by step? In the reaction: 2A+3B->C Four moles of A react with four moles B. What reactant is limiting?
回答 (1)
2017-02-15 2:15 pm
2A + 3B → C
2 moles of A reacts with 2 moles of B, i.e.
1 mole of A reacts with (3/2) moles of B.
Initial number of moles of A = 4 mol
Initial number of moles of B = 4 mol
When A completely reacts :
Number of moles of B needed = (4 mol) × (3/2) = 6 mol < 4 mol
Hence, A would not completely reacts, and B is the limiting reactant.
2 moles of A reacts with 2 moles of B, i.e.
1 mole of A reacts with (3/2) moles of B.
Initial number of moles of A = 4 mol
Initial number of moles of B = 4 mol
When A completely reacts :
Number of moles of B needed = (4 mol) × (3/2) = 6 mol < 4 mol
Hence, A would not completely reacts, and B is the limiting reactant.
收錄日期: 2021-04-18 16:04:58
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