How many moles are present in 4g of KOH??? ( K = 39u, H - 1u, 0 - 16u)?

[匿名]

2017-02-15 1:13 am

回答 (2)

不用客氣

2017-02-15 1:22 am

Molar mass of KOH = (39 + 1 + 16) g/mol = 56 g/mol

No. of moles of KOH = (4 g) / (56 g/mol) = 0.0714 mol

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lenpol7

2017-02-15 2:05 am

Moles = mass(g) / Mr

The Mr(KOH) is 39 + 1 + 16 = 56
Hence moles = 4g / 56 = 0.0714....

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