How many moles are present in 4g of KOH??? ( K = 39u, H - 1u, 0 - 16u)?
回答 (2)
2017-02-15 1:22 am
Molar mass of KOH = (39 + 1 + 16) g/mol = 56 g/mol
No. of moles of KOH = (4 g) / (56 g/mol) = 0.0714 mol
No. of moles of KOH = (4 g) / (56 g/mol) = 0.0714 mol
2017-02-15 2:05 am
Moles = mass(g) / Mr
The Mr(KOH) is 39 + 1 + 16 = 56
Hence moles = 4g / 56 = 0.0714....
The Mr(KOH) is 39 + 1 + 16 = 56
Hence moles = 4g / 56 = 0.0714....
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