How to rearrange y = - A cos B (x-c) + D to make x the subject?
回答 (3)
2017-02-11 12:35 pm
✔ 最佳答案
y = -A cos B (x-C) + Dy - D = -A cos B (x-C)
D - y = A cos B (x-C)
(D-y)/A = cos B (x-C)
cos⁻¹((D-y)/A)) = B(x-C)
cos⁻¹((D-y)/A)) / B = x - C
x = C + cos⁻¹((D-y)/A)) / B
2017-02-11 12:25 pm
y = - A cos B (x-c) + D
y - D = -A cos B (x-c)
(y-D)/-A = cos B (x-c)
arccos((y-D)/-A)) = B(x-c)
(arccos((y-D)/-A)))/B = x-c
(arccos((y-D)/-A)))/B - c = x
arccos is the same thing as cos^-1, or inverse of cos.
y - D = -A cos B (x-c)
(y-D)/-A = cos B (x-c)
arccos((y-D)/-A)) = B(x-c)
(arccos((y-D)/-A)))/B = x-c
(arccos((y-D)/-A)))/B - c = x
arccos is the same thing as cos^-1, or inverse of cos.
2017-02-11 12:12 pm
ww
收錄日期: 2021-05-01 21:27:13
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20170211041202AA5YkUF