a bag has 5 red marbles, 6 blue marbles, and 4 black marbles.?

2017-02-11 3:40 am
What is the probability of picking a blue marble, replacing it, and then picking a black marble?

回答 (13)

2017-02-11 4:08 am
Each time you will have the same distribution of marbles, because you return the drawn marble.

The probability of picking blue is 6/15 (or 2/5)
The probability of picking black is 4/15

The probability of both events happening in that order is the product:
P(blue, then black) = 2/5 x 4/15 = 8/75

Answer:
8/75
2017-02-11 3:55 am
[ 6/15 ] [ 4/15 ] = 24 / 225
2017-02-11 3:54 am
Blue: 6/15
marble replaced
Black: 4/15
so
Blue AND Black = 6/15 * 4/15 = 24/225
2017-02-11 4:12 am
Probability of Picking a blue marble 6 to 10
Probability of picking a black marble 4 to 11
2017-04-23 3:14 am
6/15 x 4/15
2017-03-28 6:02 pm
6/15 x 4/15
2017-03-06 6:30 am
blue then black

(with replacement)
(6/15)(4/15) = 24/225 ≈ ...107

(without replacement)
(6/15)(4/14) = 24/210 ≈ ...114
2017-02-24 2:17 pm
6/15 x 4/15
2017-02-16 2:42 pm
chance of getting a blue marble: 6/(5+6+4) = 6/15 = 2/5
chance of getting a black marble: 4/(5+6+4) = 4/15
answer: (2/5)*(4/15) = 8/75 =~ 0...1066666666666666666666666666666.........
2017-02-11 4:31 am
6/15 X 4/15
2017-02-11 3:52 am
Chance of getting a blue marble: 6/(5+6+4) = 6/15 = 2/5
Chance of getting a black marble: 4/(5+6+4) = 4/15
Answer: (2/5)*(4/15) = 8/75 =~ 0.1066666666666666666666666666666...
2017-02-11 3:51 am
blue then black

(with replacement)
(6/15)(4/15) = 24/225 ≈ .107

(without replacement)
(6/15)(4/14) = 24/210 ≈ .114
2017-02-11 3:42 am
Pr(Blue and Black)=Pr(Blue) x Pr(Black) = ...


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