help please?

2 complex solutions.

If the discriminant = 0, there is one real solution.
If the discriminant > 0, there are two real solutions.

If all the coefficients are real, answer (a) is correct. More specifically, there are 2 unique non-real solutions, and they are complex conjugates of each other (their sum and product are a real numbers).

However, if there are non-real coefficients, then it's impossible to answer that question without more information. For example:
x^2 + sqrt(-5)*x = 0
The discriminant is -5, and x can be -sqrt(-5) or -1. So there is 1 real solution and 1 non-real solution.

2 complex solutions

Are you some bunch of nerds or what